Li[AlH_4] is the molecular formula of which c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The $IUPAC$ name for the complex $Li[AlH_4]$ is determined by naming the cation first,followed by the anion.$1$. The cation is $Li^+$,which is nam

Vedclass · Accepted Answer

Lithium tetrahydridoaluminate $(III)$

Vedclass · Answer

(D) The $IUPAC$ name for the complex $Li[AlH_4]$ is determined by naming the cation first,followed by the anion.$1$. The cation is $Li^+$,which is named as Lithium.$2$. The anion is $[AlH_4]^-$,which is a complex anion.$3$. The ligand is $H^-$,named as hydrido. Since there are $4$ ligands,it is named as tetrahydrido.$4$. The central metal atom is Aluminum,which in an anionic complex is named as Aluminate.$5$. The oxidation state of $Al$ is calculated as: $x + 4(-1) = -1$,so $x = +3$. Thus,it is Aluminate $(III)$.Combining these,the name is Lithium tetrahydridoaluminate $(III)$.

$Li[AlH_4]$ is the molecular formula of which complex?

Similar Questions

What is the oxidation number of iron in the compound $[Fe(H_2O)_5(NO)]SO_4$?

As per $IUPAC$ nomenclature,the name of the complex $[Co(H_2O)_4(NH_3)_2]Cl_3$ is :

The oxidation states of iron atoms in compounds $(A),$ $(B)$ and $(C),$ respectively,are $x,$ $y$ and $z.$ The sum of $x, y$ and $z$ is........
$(A)$ $Na_4[Fe(CN)_5(NOS)]$
$(B)$ $Na_4[FeO_4]$
$(C)$ $[Fe_2(CO)_9]$

Oxidation number of $Fe$ in ${K_3}[Fe{(CN)_6}]$ is

The $IUPAC$ nomenclature for the complex $Na[PtBrCl(NO_2)(NH_3)]$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module