Oxidation number of Fe in {K_3}[Fe{(CN)_6}] i | vedclass

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(B) To find the oxidation number of $Fe$ in ${K_3}[Fe{(CN)_6}]$,let the oxidation state of $Fe$ be $x$.The oxidation state of $K$ is $+1$ and the oxid

Vedclass · Accepted Answer

$+3$

Vedclass · Answer

(B) To find the oxidation number of $Fe$ in ${K_3}[Fe{(CN)_6}]$,let the oxidation state of $Fe$ be $x$.The oxidation state of $K$ is $+1$ and the oxidation state of $CN^-$ is $-1$.The sum of oxidation states in a neutral complex is $0$.$3(+1) + x + 6(-1) = 0$$3 + x - 6 = 0$$x - 3 = 0$$x = +3$.Therefore,the oxidation number of $Fe$ is $+3$.

Oxidation number of $Fe$ in ${K_3}[Fe{(CN)_6}]$ is

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