The geometry and magnetic property of [NiCl_4 | vedclass

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Question

(A) The oxidation state of $Ni$ in $[NiCl_4]^{2-}$ is $+2$. The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8 4s^0$. As $Cl^{-}$ is a weak field

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tetrahedral,paramagnetic

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(A) The oxidation state of $Ni$ in $[NiCl_4]^{2-}$ is $+2$. The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8 4s^0$. As $Cl^{-}$ is a weak field ligand,pairing of electrons will not occur. The $Ni^{2+}$ ion in the complex undergoes $sp^3$ hybridisation using one $4s$ and three $4p$ orbitals. Thus,the geometry is tetrahedral. Since there are $2$ unpaired electrons in the $3d$ orbitals,the complex is paramagnetic.

The geometry and magnetic property of $[NiCl_4]^{2-}$,respectively are

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