Which of the following does not contain an sp | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine the hybridization of carbon atoms,we look at the number of sigma bonds and lone pairs attached to the carbon atom.$1$. Acetamide $(CH

Vedclass · Accepted Answer

Acetonitrile

Vedclass · Answer

(C) To determine the hybridization of carbon atoms,we look at the number of sigma bonds and lone pairs attached to the carbon atom.$1$. Acetamide $(CH_3CONH_2)$: The carbonyl carbon $(C=O)$ is $sp^2$ hybridized.$2$. Acetic acid $(CH_3COOH)$: The carbonyl carbon $(C=O)$ is $sp^2$ hybridized.$3$. Acetonitrile $(CH_3C \equiv N)$: The methyl carbon is $sp^3$ hybridized,and the nitrile carbon $(C \equiv N)$ is $sp$ hybridized. Thus,it contains no $sp^2$ hybridized carbon.$4$. Acetone $(CH_3COCH_3)$: The carbonyl carbon $(C=O)$ is $sp^2$ hybridized.Therefore,the correct option is $C$.

Which of the following does not contain an $sp^2$ hybridized carbon?

Similar Questions

The hybridisations of carbon-$2$ in $P$ and $Q$ are respectively:

The compounds containing $sp$-hybridised carbon atom are:
$(I)$ $H_3C-N(CH_3)-CHO$
$(II)$ Pyridine
$(III)$ $H_3C-CN$
$(IV)$ $H_2C=C=CH-CH_3$

Determine the hybridization of the $C_3$ and $C_6$ carbon atoms in the given structure,respectively. (Numbering starts from the left end of the longest chain containing the principal functional group).

Allyl isocyanide contains $......... \sigma$ and $......... \pi$ bonds.

The hybridization of carbon involved in the $C_2-C_3$ single bond in the molecule $CH \equiv C-CH=CH_2$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module