CH_3-CH(CH_3)-CH(OH)-CH_3 xrightarrow[350^cir | vedclass

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(A) $1.$ Dehydration of $3$-methylbutan-$2$-ol $(CH_3-CH(CH_3)-CH(OH)-CH_3)$ using $Al_2O_3$ at $350^\circ C$ yields $2$-methylbut-$2$-ene $(CH_3-C(CH

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$CH_3-C(OH)(CH_3)-CH_2-CH_3$

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(A) $1.$ Dehydration of $3$-methylbutan-$2$-ol $(CH_3-CH(CH_3)-CH(OH)-CH_3)$ using $Al_2O_3$ at $350^\circ C$ yields $2$-methylbut-$2$-ene $(CH_3-C(CH_3)=CH-CH_3)$ as the major product according to Saytzeff's rule. $2.$ Addition of $HI$ to $2$-methylbut-$2$-ene follows Markovnikov's rule,where the $I^-$ attaches to the more substituted carbon,forming $2$-iodo-$2$-methylbutane $(CH_3-CI(CH_3)-CH_2-CH_3)$. $3.$ Reaction with $AgOH$ (moist $Ag_2O$) results in nucleophilic substitution of the iodide group with a hydroxyl group,forming $2$-methylbutan-$2$-ol $(CH_3-C(OH)(CH_3)-CH_2-CH_3)$.

$CH_3-CH(CH_3)-CH(OH)-CH_3$ $\xrightarrow[350^\circ C]{Al_2O_3} (A)$ $\xrightarrow[(ii) AgOH]{(i) HI} (B)$
Product $(B)$ of the above reaction is:

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$CH_3-CH(CH_3)-CH(OH)-CH_3$ $\xrightarrow[350^\circ C]{Al_2O_3} (A)$ $\xrightarrow[(ii) AgOH]{(i) HI} (B)$ Product $(B)$ of the above reaction is: