On strong heating,ZnCl_2 cdot 2H_2O gives ... | vedclass

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(D) When $ZnCl_2 \cdot 2H_2O$ is heated strongly,it undergoes hydrolysis due to the presence of water of crystallization.The reaction is as follows:$Z

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$ZnO$

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(D) When $ZnCl_2 \cdot 2H_2O$ is heated strongly,it undergoes hydrolysis due to the presence of water of crystallization.The reaction is as follows:$ZnCl_2 \cdot 2H_2O \xrightarrow{\Delta} Zn(OH)Cl + HCl + H_2O$Further heating of $Zn(OH)Cl$ leads to the formation of zinc oxide $(ZnO)$:$2Zn(OH)Cl \xrightarrow{\Delta} ZnO + ZnCl_2 + H_2O$However,in the context of standard chemistry problems regarding the dehydration of hydrated metal chlorides,the primary product formed upon strong heating is $ZnO$.

List-$I$ (Reactions)	List-$II$ (Methods)
$A$. $Mg(HCO_3)_2 \rightarrow Mg(OH)_2 \downarrow + 2 CO_2 \uparrow$	$I$. Clark's method
$B$. $M^{2+} + Na_4P_6O_{18}^{2-} \rightarrow [Na_2MP_6O_{18}]^{2-} + 2 Na^{+}$	$II$. Ion exchange method
$C$. $Ca(HCO_3)_2 + Ca(OH)_2 \rightarrow 2 CaCO_3 + 2 H_2O$	$III$. Boiling
$D$. $2 NaZ + Ca^{2+}_{(aq)} \rightarrow 2 Na^{+} + CaZ_2$ ($Z$ = Zeolite)	$IV$. Calgon's method

On strong heating,$ZnCl_2 \cdot 2H_2O$ gives .......

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