Addition of $HI$ on the double bond of propene yields isopropyl iodide and not $n$-propyl iodide as the major product. This is because the addition proceeds through

  • A
    $A$ more stable carbonium ion
  • B
    $A$ more stable carbanion
  • C
    $A$ more stable free radical
  • D
    None of the above being a concerted reaction

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