An organic compound has a molar mass of 108 | vedclass

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Question

(A) $1$. Calculate the moles of each element in a $100 \ g$ sample based on the given weight ratio $(9:1:3.5)$:$Moles \ of \ C = \frac{9}{12} = 0.75$$

Vedclass · Accepted Answer

$C_6H_8N_2$

Vedclass · Answer

(A) $1$. Calculate the moles of each element in a $100 \ g$ sample based on the given weight ratio $(9:1:3.5)$:$Moles \ of \ C = \frac{9}{12} = 0.75$$Moles \ of \ H = \frac{1}{1} = 1.0$$Moles \ of \ N = \frac{3.5}{14} = 0.25$$2$. Determine the simplest ratio by dividing by the smallest value $(0.25)$:$C : H : N = \frac{0.75}{0.25} : \frac{1.0}{0.25} : \frac{0.25}{0.25} = 3 : 4 : 1$$3$. The empirical formula is $C_3H_4N_1$. The empirical formula mass is $(3 	imes 12) + (4 	imes 1) + (1 	imes 14) = 36 + 4 + 14 = 54 \ g \ mol^{-1}$.$4$. Calculate the $n$ factor: $n = \frac{	ext{Molar mass}}{	ext{Empirical formula mass}} = \frac{108}{54} = 2$.$5$. The molecular formula is $n 	imes (C_3H_4N_1) = 2 	imes (C_3H_4N_1) = C_6H_8N_2$.

An organic compound has a molar mass of $108 \ g \ mol^{-1}$. The atoms $C, H,$ and $N$ are present in the weight ratio of $9 : 1 : 3.5$. What is the molecular formula of the compound?

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