An organic compound gave the following result | vedclass

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(C) To find the empirical formula,we calculate the number of moles of each element by dividing the percentage by its atomic mass: $C: 53.3 / 12 = 4.44

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$C_2H_7N$

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(C) To find the empirical formula,we calculate the number of moles of each element by dividing the percentage by its atomic mass: $C: 53.3 / 12 = 4.44$ $H: 15.6 / 1 = 15.6$ $N: 31.1 / 14 = 2.22$ Dividing by the smallest value $(2.22)$: $C: 4.44 / 2.22 = 2$ $H: 15.6 / 2.22 \approx 7$ $N: 2.22 / 2.22 = 1$ The empirical formula is $C_2H_7N$. The empirical formula mass is $(2 	imes 12) + (7 	imes 1) + 14 = 24 + 7 + 14 = 45$. Since the empirical formula mass equals the given molecular weight $(45)$,the molecular formula is the same as the empirical formula,which is $C_2H_7N$.

An organic compound gave the following results: $C = 53.3\%$,$H = 15.6\%$,$N = 31.1\%$. The molecular weight of the compound is $45$. What is the molecular formula of the compound?

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