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(D) Gold sol is a negatively charged sol. According to the Hardy-Schulze rule,the coagulating power of an electrolyte depends on the valency of the op

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$MgCl_2$

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(D) Gold sol is a negatively charged sol. According to the Hardy-Schulze rule,the coagulating power of an electrolyte depends on the valency of the oppositely charged ion (cation in this case). Greater the valency of the flocculating ion,greater is its coagulating power. The cations provided by the electrolytes are: $A: K^+$ (valency $1$) $B: K^+$ (valency $1$) $C: K^+$ (valency $1$) $D: Mg^{2+}$ (valency $2$) Since $Mg^{2+}$ has a higher valency than $K^+$,$MgCl_2$ is the most effective electrolyte for the coagulation of negatively charged gold sol.

List-$I$	List-$II$
$(A)$ Solid dispersed in liquid	$(I)$ Emulsion
$(B)$ Liquid dispersed in liquid	$(II)$ Foam
$(C)$ Gas dispersed in liquid	$(III)$ Gel
$(D)$ Liquid dispersed in solid	$(IV)$ Sol
-	$(V)$ Aerosol

Which of the following is the most effective electrolyte for the coagulation of gold sol?

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