Which ion has the maximum precipitation (floc | vedclass

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(A) According to the Hardy-Schulze rule,the coagulating power of an ion is directly proportional to its valency (charge) for the coagulation of a coll

Vedclass · Accepted Answer

$Br^{-}$

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(A) According to the Hardy-Schulze rule,the coagulating power of an ion is directly proportional to its valency (charge) for the coagulation of a colloidal solution of opposite charge.For a positively charged colloidal solution,the coagulating power of anions follows the order: $[Fe(CN)_6]^{4-} > [Fe(CN)_6]^{3-} > CO_3^{2-} > Br^-$.The precipitation (flocculation) value is inversely proportional to the coagulating power.Therefore,the ion with the lowest charge will have the maximum precipitation value.Comparing the charges: $Br^-$ $(-1)$,$CO_3^{2-}$ $(-2)$,$[Fe(CN)_6]^{3-}$ $(-3)$,$[Fe(CN)_6]^{4-}$ $(-4)$.Since $Br^-$ has the minimum charge,it has the maximum precipitation value.

Which ion has the maximum precipitation (flocculation) value for the precipitation of a positively charged colloidal solution?

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