What is the product $C$ in the following reaction?
$CH_3Br$ $\xrightarrow{KCN} A$ $\xrightarrow{H_3O^+} B$ $\xrightarrow{LiAlH_4} C$

Consider the following reaction:
$\text{Propanal} + \text{Methanal}$ $\xrightarrow[\text{(ii)}\Delta, \text{(iii)}\text{NaCN}, \text{(iv)}\text{H}_3\text{O}^+]{\text{(i)}\text{dil. NaOH}} \text{Product } B (C_5H_8O_3)$
The correct statement for product $B$ is:

Assertion: Acetamide has a more polar $C=O$ group than ethyl acetoacetate.
Reason: $-\ddot{N}H_{2}$ is more electron-donating than $-\ddot{O}C_{2}H_{5}$.

Amongst the following,the total number of compounds soluble in aqueous $NaOH$ at room temperature is:
$(I)$ Benzaldehyde
$(II)$ $1$-Naphthol
$(III)$ $4$-(Dimethylamino)phenol
$(IV)$ $4$-Methylphenol
$(V)$ Benzoic acid
$(VI)$ $N,N$-Dimethylcyclohexanamine
$(VII)$ $1$-Naphthoic acid
$(VIII)$ $1,4$-Di-tert-butylbenzene
$(IX)$ $1$-Naphthylmethanol

Benzocaine has been used as a component of appetite suppressants,burn and sunburn remedies. Benzocaine is:

An organic acid $P$ $(C_{11}H_{12}O_2)$ can easily be oxidized to a dibasic acid which reacts with ethylene glycol to produce a polymer,dacron. Upon ozonolysis,$P$ gives an aliphatic ketone as one of the products. $P$ undergoes the following reaction sequences to furnish $R$ via $Q$. The compound $P$ also undergoes another set of reactions to produce $S$.
$(1)$ The compound $R$ is
$(2)$ The compound $S$ is
Give the answer for questions $(1)$ and $(2)$.