The C-H bond distance is the longest in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The $C-H$ bond length depends on the hybridization of the carbon atom. As the $s$-character in the hybrid orbital increases,the bond length decrea

Vedclass · Accepted Answer

$C_2H_4Br_2$

Vedclass · Answer

(C) The $C-H$ bond length depends on the hybridization of the carbon atom. As the $s$-character in the hybrid orbital increases,the bond length decreases. $C_2H_2$ ($sp$ hybridization,$50\% \ s$-character),$C_2H_4$ ($sp^2$ hybridization,$33.3\% \ s$-character),and $C_6H_6$ ($sp^2$ hybridization) have shorter $C-H$ bonds. In $C_2H_4Br_2$ ($1$,$2$-dibromoethane),the carbon atoms are $sp^3$ hybridized ($25\% \ s$-character). Since $sp^3$ hybridized carbon has the least $s$-character,the $C-H$ bond is the longest. Therefore,the correct option is $C$.

The $C-H$ bond distance is the longest in

Similar Questions

Which type of hybridization occurs in diborane $(B_2H_6)$?

The hybridization of nitrogen atoms in $NO^{+}_2$,$NO^{-}_3$,and $NH^{+}_4$ respectively is:

What is the hybridization of sulfur in $SO_2$?

The hybridisations of $N$-orbitals in $NO_3^{-}$,$NO_2^{-}$ and $NH_4^{+}$ respectively are

The hybridization of atomic orbitals of nitrogen in $NO_2^+$,$NO_3^-$,and $NH_4^+$ are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module