The molar conductivities at infinite dilution for $AgNO_3$,$AgCl$,and $NaCl$ are $116.5$,$121.6$,and $110.3 \ S \ cm^2 \ mol^{-1}$ respectively. The molar conductivity of $NaNO_3$ is...

  • A
    $111.4$
  • B
    $105.2$
  • C
    $130.6$
  • D
    $150.2$

Explore More

Similar Questions

The cell constant of a given cell is $0.47 \, cm^{-1}$. The resistance of a solution placed in this cell is measured to be $31.6 \, \Omega$. The conductivity of the solution (in $S \, cm^{-1}$ where $S$ has usual meaning) is

What is the cell constant of $\frac{N}{10}$ $KCl$ solution at $25^{\circ} C$,if conductivity and resistance of a solution is $0.0112 \ \Omega^{-1} cm^{-1}$ and $55.0 \ \Omega$ respectively (in $cm^{-1}$)?

Molar conductivity of $0.04 \ M \ BaCl_2$ solution is $230 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ at $27^{\circ} C$. What is its conductivity?

Calculate the cell constant of a conductivity cell containing $0.01 \ M \ AgNO_3$ solution having a resistance of $1440 \ \Omega$ and a conductivity of $0.001262 \ \Omega^{-1} \ cm^{-1}$. (in $cm^{-1}$)

The specific conductivity of $N/10$ $KCl$ solution at $20\,^oC$ is $0.0212\,ohm^{-1}\,cm^{-1}$ and the resistance of the cell containing this solution at $20\,^oC$ is $55\,ohm$. The cell constant is ............. $cm^{-1}$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo