Calculate the cell constant of a conductivity cell containing $0.01 \ M \ AgNO_3$ solution having a resistance of $1440 \ \Omega$ and a conductivity of $0.001262 \ \Omega^{-1} \ cm^{-1}$. (in $cm^{-1}$)

  • A
    $1.014$
  • B
    $0.883$
  • C
    $1.817$
  • D
    $1.411$

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Similar Questions

The following figure shows the dependence of molar conductance of two electrolytes on concentration. $\Lambda_m^0$ is the limiting molar conductivity. The number of incorrect statement$(s)$ from the following is $...........$
$(A)$ $\Lambda_m^0$ for electrolyte $A$ is obtained by extrapolation.
$(B)$ For electrolyte $B$,the $\Lambda_m$ vs $\sqrt{c}$ graph is a straight line with an intercept equal to $\Lambda_m^0$.
$(C)$ At infinite dilution,the value of the degree of dissociation approaches zero for electrolyte $B$.
$(D)$ $\Lambda_m^0$ for any electrolyte $A$ or $B$ can be calculated using $\lambda^0$ for individual ions.

Identify True $(T)$ or False $(F)$ for the following statements :
$(i)$ As temperature of solution is more,then conductivity is more.
$(ii)$ Conductivity of $Cu \propto$ temperature.
$(iii)$ As temperature increases,conductivity of $Cu$ decreases.

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Conductivity of a saturated solution of a sparingly soluble salt $AB$ at $298 \ K$ is $1.85 \times 10^{-5} \ S \ m^{-1}$. Solubility product of the salt $AB$ at $298 \ K$ is. Given $\Lambda_{m}^{\circ}(AB) = 140 \times 10^{-4} \ S \ m^{2} \ mol^{-1}$.

Calculate the cell constant of a conductivity cell containing $0.1 \ M$ $KCl$ solution having a resistance of $60 \ \Omega$ and a conductivity of $0.014 \ \Omega^{-1} \ cm^{-1}$ at $25^{\circ} \ C$. (in $cm^{-1}$)

What is metallic or electronic conductivity? On what factors does it depend?

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