The dimensional formula of $\sqrt{\mu_r K}$ is equal to:

  • A
    $M^0 L^0 T^0$
  • B
    $M^0 L^1 T^{-1}$
  • C
    $M^0 L^{-1} T^1$
  • D
    $M^0 L^0 T^0$ (dimensionless)

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Similar Questions

The two principal thrusts in physics are

To determine the Young's modulus of a wire,the formula is $Y = \frac{FL}{A\Delta L}$,where $L$ is the length,$A$ is the area of cross-section of the wire,and $\Delta L$ is the change in length of the wire when stretched with a force $F$. The conversion factor to change the unit of Young's modulus from $CGS$ to $MKS$ system is $x \times 10^{-1} \ N/m^2$. Find the value of $x$.

Match List $I$ with List $II$:
List $I$ List $II$
$(A)$ Young's Modulus $(Y)$ $(I)$ $[M L^{-1} T^{-1}]$
$(B)$ Co-efficient of Viscosity $(\eta)$ $(II)$ $[M L^2 T^{-1}]$
$(C)$ Planck's Constant $(h)$ $(III)$ $[M L^{-1} T^{-2}]$
$(D)$ Work Function $(\phi)$ $(IV)$ $[M L^2 T^{-2}]$

Choose the correct answer from the options given below:

Match the following (Take the relative strength of the strongest fundamental forces in nature as $1$):
$I$ (Fundamental forces in nature)$II$ (Relative strength)
$(A)$ Strong nuclear force$(e)$ $10^{-2}$
$(B)$ Weak nuclear force$(f)$ $1$
$(C)$ Electromagnetic force$(g)$ $10^{10}$
$(D)$ Gravitational force$(h)$ $10^{-13}$
$(i)$ $10^{-39}$

The correct match is:

The unit $J \cdot s^2$ corresponds to which physical quantity?

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