When a point source of monochromatic light is | vedclass

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(B, C) The stopping potential depends only on the frequency of the incident light,not on its intensity. Since the source remains the same (monochromat

Vedclass · Accepted Answer

The stopping potential will remain $0.6 \ V$.

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(B, C) The stopping potential depends only on the frequency of the incident light,not on its intensity. Since the source remains the same (monochromatic),the frequency is constant. Therefore,the stopping potential remains $0.6 \ V$.The saturation photocurrent $(I_s)$ is directly proportional to the intensity of the incident light. The intensity $(I)$ of a point source follows the inverse square law,$I \propto 1/d^2$.Given the initial distance $d_1 = 0.2 \ m$ and the final distance $d_2 = 0.6 \ m$,the ratio of the distances is $d_2/d_1 = 0.6/0.2 = 3$.Thus,the new intensity $I_2 = I_1 / (3^2) = I_1 / 9$.Since $I_s \propto I$,the new saturation current $I_{s2} = I_{s1} / 9 = 18 \ mA / 9 = 2 \ mA$.

When a point source of monochromatic light is at a distance of $0.2 \ m$ from a photoelectric cell,the stopping potential and saturation photocurrent are $0.6 \ V$ and $18 \ mA$ respectively. If the same source is placed $0.6 \ m$ away from the photoelectric cell,then:

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