The momentum of a photon with frequency 1.5 t | vedclass

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Question

(A) The momentum $p$ of a photon is given by the relation $p = \frac{h}{\lambda}$.Since the speed of light $c = f \lambda$,we have $\lambda = \frac{c}

Vedclass · Accepted Answer

$3.3 	imes 10^{-29} \ kg \ m/s$

Vedclass · Answer

(A) The momentum $p$ of a photon is given by the relation $p = \frac{h}{\lambda}$.Since the speed of light $c = f \lambda$,we have $\lambda = \frac{c}{f}$.Substituting this into the momentum formula,we get $p = \frac{hf}{c}$.Given: $h = 6.63 	imes 10^{-34} \ J \ s$,$f = 1.5 	imes 10^{13} \ Hz$,and $c = 3 	imes 10^8 \ m/s$.$p = \frac{6.63 	imes 10^{-34} 	imes 1.5 	imes 10^{13}}{3 	imes 10^8}$.$p = \frac{9.945 	imes 10^{-21}}{3 	imes 10^8} \approx 3.315 	imes 10^{-29} \ kg \ m/s$.Rounding to the given options,the correct value is $3.3 	imes 10^{-29} \ kg \ m/s$.

The momentum of a photon with frequency $1.5 \times 10^{13} \ Hz$ is .......

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