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(D) For the emission of photoelectrons from a surface, the wavelength of the incident light $\lambda$ must be  <  or equal to the threshold wavelength

Vedclass · Accepted Answer

Both $(A)$ and $(B)$

Vedclass · Answer

(D) For the emission of photoelectrons from a surface, the wavelength of the incident light $\lambda$ must be  Given, $\lambda_0 = 5200\, 	ext{\AA}$.Ultraviolet light has a wavelength range typically between $100\, 	ext{\AA}$ and $4000\, 	ext{\AA}$, which is  Infrared light has a wavelength greater than $7000\, 	ext{\AA}$, which is greater than $5200\, 	ext{\AA}$.Therefore, light from an ultraviolet lamp (regardless of power, as power only affects the number of photoelectrons, not the emission condition) will cause emission.Thus, both $(A)$ and $(B)$ are correct.

The threshold wavelength for the emission of photoelectrons from a material is $5200\, \text{\AA}$. Which of the following monochromatic light sources will cause the emission of photoelectrons from this surface?

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