According to Einstein's photoelectric equatio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Einstein's photoelectric equation is given by $K_{max} = h
u - \phi_0$,where $K_{max}$ is the maximum kinetic energy,$h$ is Planck's constant,$

Vedclass · Accepted Answer

is the same for all metals and is independent of the intensity of radiation.

Vedclass · Answer

(D) Einstein's photoelectric equation is given by $K_{max} = h
u - \phi_0$,where $K_{max}$ is the maximum kinetic energy,$h$ is Planck's constant,$
u$ is the frequency of incident radiation,and $\phi_0$ is the work function of the metal.Comparing this with the equation of a straight line $y = mx + c$,we get $K_{max} = h
u - \phi_0$.Here,the slope $m = h$ (Planck's constant).Since Planck's constant $h$ is a universal constant,the slope of the graph is the same for all metals.Furthermore,the slope is independent of the intensity of the incident radiation.

According to Einstein's photoelectric equation,the graph of the maximum kinetic energy of emitted photoelectrons versus the frequency of incident radiation is a straight line. Its slope . . . . . .

Similar Questions

Cut-off potentials for a metal in the photoelectric effect for light of wavelengths $\lambda_1$,$\lambda_2$,and $\lambda_3$ are found to be $V_1$,$V_2$,and $V_3$ volts. If $V_1$,$V_2$,and $V_3$ are in Arithmetic Progression,then $\lambda_1$,$\lambda_2$,and $\lambda_3$ will be in:

When light is incident on a surface,photoelectrons are emitted. For these photoelectrons:

The work function of a metal is $1 \; eV$. Light of wavelength $3000 \; \mathring{A}$ is incident on this metal surface. The velocity of the emitted photo-electrons will be:

Which of the following statements is not true about stopping potential $(V_0)$?

Light of two different frequencies whose photons have energies $1 \text{ eV}$ and $2.5 \text{ eV}$ respectively,successively illuminate a metallic surface whose work function is $0.5 \text{ eV}$. The ratio of the maximum speeds of the emitted electrons will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module