What is the probability that a randomly selected leap year has $53$ Sundays or $53$ Mondays (in $/7$)?

Each of the two boxes $A$ and $B$ contain $10$ chits numbered $1$ to $10$. If one chit is drawn at random from each of $A$ and $B$,then the probability that the number on the chit drawn from $A$ is smaller than the number on the chit drawn from $B$,is

If two dice are thrown simultaneously,then the probability that the sum of the numbers which come up on the dice is more than $5$ is:

Let $A$ and $B$ be two events such that $P(\overline{A \cup B}) = \frac{1}{6}$,$P(A \cap B) = \frac{1}{4}$,and $P(\bar{A}) = \frac{1}{4}$,where $\bar{A}$ stands for the complement of event $A$. Then events $A$ and $B$ are

Three coins are tossed. Describe two events which are mutually exclusive.

The probability that a non-leap year selected at random will have $53$ Sundays is