What is the solution set of the inequality $x^2 + 2|x| - 15 \geq 0$?

The common solution set of the inequations $x^2-4x \leq 12$ and $x^2-2x \geq 15$ taken together is

Let $\alpha$ and $\beta$ be the distinct roots of the equation $x^2 - (t^2 - 5t + 6)x + 1 = 0$,where $t \in \mathbb{R}$,and $a_n = \alpha^n + \beta^n$. Then the minimum value of $\frac{a_{2023} + a_{2025}}{a_{2024}}$ is

The set of values of $x$ for which the inequalities $x^2-3x-10 < 0$ and $10x-x^2-16 > 0$ hold simultaneously is:

For the inequality $2^{\log_{\sqrt{2}}(x - 1)} > x + 5$,the set of real values of $x$ is:

The solution set of the inequation $3^x+3^{1-x}-4 < 0$ contained in $\mathbb{R}$ is