The position vector of point C relative to B | vedclass

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(A) Given that the position vector of $C$ relative to $B$ is $\vec{BC} = \hat{i} + \hat{j}$.The position vector of $B$ relative to $A$ is $\vec{AB} =

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$2\hat{i}$

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(A) Given that the position vector of $C$ relative to $B$ is $\vec{BC} = \hat{i} + \hat{j}$.The position vector of $B$ relative to $A$ is $\vec{AB} = \hat{i} - \hat{j}$.We need to find the position vector of $C$ relative to $A$,which is $\vec{AC}$.Using the triangle law of vector addition,we have:$\vec{AC} = \vec{AB} + \vec{BC}$.Substituting the given values:$\vec{AC} = (\hat{i} - \hat{j}) + (\hat{i} + \hat{j})$.Simplifying the expression:$\vec{AC} = \hat{i} + \hat{i} - \hat{j} + \hat{j} = 2\hat{i}$.Thus,the position vector of $C$ relative to $A$ is $2\hat{i}$.

The position vector of point $C$ relative to $B$ is $(\hat{i} + \hat{j})$ and the position vector of $B$ relative to $A$ is $(\hat{i} - \hat{j})$. The position vector of $C$ relative to $A$ is:

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