If $\binom{n-1}{4}, \binom{n-1}{5}$ and $\binom{n-1}{6}$ are in Arithmetic Progression,then find the relation.

  • A
    $\binom{n+1}{6} = 2\binom{n-1}{5}$
  • B
    $2\binom{n+1}{6} = \binom{n-1}{5}$
  • C
    $\binom{n+1}{6} = 4\binom{n-1}{5}$
  • D
    $4\binom{n+1}{6} = \binom{n-1}{5}$

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