In Young's double-slit experiment,if one slit is covered with a blue filter and the other with a yellow filter,then the interference pattern will be:

In Young's double-slit experiment,the slits are separated by $0.2 \, cm$ and illuminated by light of wavelength $\lambda = 5896 \, \mathring{A}$. What is the fringe width on a screen placed $1 \, m$ away from the plane of the slits? What will be the fringe width if the entire system is immersed in water (in $, mm$)? (Refractive index of water $\mu_w = 4/3$)

If fringe width is $0.4 \,mm$, the distance between the fifth bright and third dark band on the same side is: (in $\,mm$)

If the slit widths of $YDSE$ are in the ratio $1:4$,then the ratio of maximum to minimum intensity on the screen is: (in $:1$)

$A$ beam of electrons is used in $Y.D.S.E.$ The slit width is $d$. When the velocity of the electrons is increased,then:

The figure shows a schematic diagram of Young's Double Slit Experiment. Identify the correct statement$(s)$ if the source slit $S$ is moved closer to the slits $S_1$ and $S_2$,i.e.,the distance $\ell$ decreases.