If fringe width is $0.4 \,mm$, the distance between the fifth bright and third dark band on the same side is: (in $\,mm$)

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $4$

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In a Young's double-slit experiment,the fringe width is $0.8 \, mm$ when light of wavelength $6000 \, \mathring{A}$ is used,and the screen is at a distance of $2.5 \, m$. If the experiment is performed in a liquid with a refractive index of $1.6$,the new fringe width will be.....$mm$.

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