If vec{A} + vec{B} = vec{C} and A + B = C,wha | vedclass

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(A) The magnitude of the resultant vector $\vec{C} = \vec{A} + \vec{B}$ is given by the formula $C = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$,where $	heta

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(A) The magnitude of the resultant vector $\vec{C} = \vec{A} + \vec{B}$ is given by the formula $C = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$,where $	heta$ is the angle between $\vec{A}$ and $\vec{B}$.Given that $C = A + B$,we substitute this into the equation:$A + B = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$Squaring both sides:$(A + B)^2 = A^2 + B^2 + 2AB \cos 	heta$$A^2 + B^2 + 2AB = A^2 + B^2 + 2AB \cos 	heta$Subtracting $A^2 + B^2$ from both sides:$2AB = 2AB \cos 	heta$Assuming $A, B 
eq 0$,we divide by $2AB$:$1 = \cos 	heta$Therefore,$	heta = 0$.

If $\vec{A} + \vec{B} = \vec{C}$ and $A + B = C$,what is the angle between $\vec{A}$ and $\vec{B}$?

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