The value of frac{d^2}{dx^2} (4x^3 - 3x^2 + 2 | vedclass

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Question

(B) Let $f(x) = 4x^3 - 3x^2 + 2x + 1$.First derivative: $\frac{d}{dx} (4x^3 - 3x^2 + 2x + 1) = 12x^2 - 6x + 2$.Second derivative: $\frac{d}{dx} (12x^2

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(B) Let $f(x) = 4x^3 - 3x^2 + 2x + 1$.First derivative: $\frac{d}{dx} (4x^3 - 3x^2 + 2x + 1) = 12x^2 - 6x + 2$.Second derivative: $\frac{d}{dx} (12x^2 - 6x + 2) = 24x - 6$.

The value of $\frac{d^2}{dx^2} (4x^3 - 3x^2 + 2x + 1)$ is ..... (in $x - 6$)

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