(C) The resistance $R_t$ at temperature $t$ is given by the formula: $R_t = R_0(1 + \alpha t)$. Given that $R_t = 3R_0$ and $\alpha = 4 \times 10^{-3

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(C) The resistance $R_t$ at temperature $t$ is given by the formula: $R_t = R_0(1 + \alpha t)$. Given that $R_t = 3R_0$ and $\alpha = 4 \times 10^{-3}{}^{\circ} C^{-1}$. Substituting these values into the equation: $3R_0 = R_0(1 + 4 \times 10^{-3} \times t)$ $3 = 1 + 4 \times 10^{-3} \times t$ $2 = 4 \times 10^{-3} \times t$ $t = \frac{2}{4 \times 10^{-3}} = \frac{2000}{4} = 500 ^{\circ} C$. Therefore, the temperature is $500 ^{\circ} C$.

Class 12 Physics Current Electricity Resistance of wire, Resistivity and Conductivity

Medium

At what temperature $(^{\circ} C)$ will the resistance of a copper wire become $3$ times its resistance at $0^{\circ} C$? (Given: Temperature coefficient of resistance $\alpha = 4 \times 10^{-3} {}^{\circ} C^{-1}$)

A
$400$
B
$450$
C
$500$
D
$550$

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Current Electricity

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Resistance of wire, Resistivity and Conductivity

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At what temperature $(^{\circ} C)$ will the resistance of a copper wire become $3$ times its resistance at $0^{\circ} C$? (Given: Temperature coefficient of resistance $\alpha = 4 \times 10^{-3} {}^{\circ} C^{-1}$)

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