The refractive index of glass for red light i | vedclass

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Question

(A) For a thin prism,the angle of deviation $D$ is given by the formula $D = (\mu - 1) A$,where $\mu$ is the refractive index and $A$ is the prism ang

Vedclass · Accepted Answer

$D_1 < D_2$

Vedclass · Answer

(A) For a thin prism,the angle of deviation $D$ is given by the formula $D = (\mu - 1) A$,where $\mu$ is the refractive index and $A$ is the prism angle.Since the refractive index for blue light $(\mu_{blue} = 1.525)$ is greater than the refractive index for red light $(\mu_{red} = 1.520)$,we have $\mu_{blue} > \mu_{red}$.Substituting these into the deviation formula,we get $D_{blue} > D_{red}$.Given that $D_1$ is the deviation for red light and $D_2$ is the deviation for blue light,it follows that $D_2 > D_1$ or $D_1 < D_2$.

The refractive index of glass for red light is $1.520$ and for blue light is $1.525$. Let $D_1$ and $D_2$ be the angles of deviation for red and blue light,respectively,in a prism of this glass. Then:

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