$A$ spectrum is formed by a prism of dispersive power $\omega$. If the angle of deviation is $\delta$,then the angular dispersion is

If the angle of minimum deviation produced by an equilateral prism is equal to the angle of the prism,then the refractive index of the material of the prism is nearly

Find the angle of minimum deviation for an equilateral prism made of a material of refractive index $1.732$. What is the angle of incidence for this deviation?

$A$ prism of refractive index $n_{1}$ and another prism of refractive index $n_{2}$ are stuck together (as shown in the figure). $n_{1}$ and $n_{2}$ depend on $\lambda$, the wavelength of light, according to the relation:
${n}_{1}=1.2+\frac{10.8 \times 10^{-14}}{\lambda^{2}} \text{ and } {n}_{2}=1.45+\frac{1.8 \times 10^{-14}}{\lambda^{2}}$
The wavelength for which rays incident at any angle on the interface $BC$ pass through without bending at that interface will be $....\,nm.$

Derive the expression $\delta = i + e - A$ for a prism.

If the prism angle is $60^{\circ}$ and the angle of minimum deviation is $40^{\circ}$, what is the angle of refraction in degrees?