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Question

(B) When an observer in a rarer medium (air) looks at an object in a denser medium (water),the apparent depth of the object is given by the formula $d

Vedclass · Accepted Answer

$h_1 + \frac{h_2}{\mu}$

Vedclass · Answer

(B) When an observer in a rarer medium (air) looks at an object in a denser medium (water),the apparent depth of the object is given by the formula $d' = \frac{d}{\mu}$,where $d$ is the real depth and $\mu$ is the refractive index of the denser medium with respect to the rarer medium.Here,the real depth of the fish is $h_2$.So,the apparent depth of the fish as seen by the bird is $h_2' = \frac{h_2}{\mu}$.The bird is at a height $h_1$ above the water surface.Therefore,the total distance of the fish as observed by the bird is the sum of the bird's height and the apparent depth of the fish.Total distance = $h_1 + \frac{h_2}{\mu}$.

$A$ bird is looking at a fish underwater from the air. $h_1$ is the height of the bird above the water surface and $h_2$ is the depth of the fish below the water surface. If $\mu$ is the refractive index of water with respect to air,then the distance of the fish as observed by the bird is:

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