In a $CE$ circuit,the collector of a transistor is kept at a constant voltage $V_C = 1.5 \ V$. When the base current changes from $100 \ \mu A$ to $150 \ \mu A$,the collector current changes from $5 \ mA$ to $10 \ mA$. The current gain $\beta$ for this transistor is:

In an $n-p-n$ transistor,$200$ electrons enter the emitter in $10^{-8} \ s$. If $1 \%$ of electrons are lost in the base,then the current that enters the emitter and the current amplification factor are respectively $\left[e=1.6 \times 10^{-19} \ C\right]$

In a transistor,if $\frac{I_C}{I_E} = \alpha$ and $\frac{I_C}{I_B} = \beta$. If $\alpha$ varies between $\frac{20}{21}$ and $\frac{100}{101}$,then the value of $\beta$ lies between:

In a common emitter amplifier,a.c. current gain is $40$ and input resistance is $2 \ k\Omega$. The load resistance is given as $10 \ k\Omega$. Then the voltage gain is

The thinnest part of a transistor is . . . . . .

Identify the terminals of this $BJT$ and the type of $BJT$ $(NPN$ or $PNP)$. The multimeter is set to diode test mode (indicated by the symbol),and the black probe is connected to the $COM$ port while the red probe is connected to the $V\Omega$ port. Based on the connections shown in the image,determine the terminal configuration (from left to right) and the transistor type.