For a given transistor,if $\alpha = 0.95$,find the common emitter current gain $\beta$.

An $n-p-n$ transistor is connected in common-emitter configuration as shown in the figure. If the collector current is $5 \text{ mA}$,$V_{BE} = 0.6 \text{ V}$,$V_{CE} = 3 \text{ V}$,and the common-emitter current amplification factor $\beta = 50$,then the values of $R_1$ and $R_2$ are respectively.

In a common emitter transistor amplifier circuit,the current gain $\alpha = 0.8$. If the base current changes by $3 \mu A$,then the collector current changes by: (in $\mu A$)

In common emitter mode of a transistor, the d.c. current gain is $20$, and the emitter current is $7 \,mA$. The collector current is (in $/ 3 \,mA$)

In an $n-p-n$ transistor circuit,the collector current is $10 \text{ mA}$. If $95\%$ of the electrons emitted reach the collector,then the base current is nearly: (in $mA$)

In a transistor circuit,when the base current is increased by $50 \mu A$ keeping the collector voltage fixed at $2 \ V$,the collector current increases by $1 \ mA$. The current gain of the transistor is