(A) The amplification factor $(\mu)$ is given by $\mu = g_m \times r_p$.Substituting the given values: $\mu = 2.5 \times 10^{-3} \text{ A/V} \times 20

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(A) The amplification factor $(\mu)$ is given by $\mu = g_m \times r_p$.Substituting the given values: $\mu = 2.5 \times 10^{-3} \text{ A/V} \times 20 \times 10^3 \, \Omega = 50$.The voltage gain $(A)$ of a triode amplifier is given by $A = \frac{\mu R_L}{r_p + R_L}$.Given $A = 10$, we have $10 = \frac{50 R_L}{20 + R_L}$.Multiplying both sides by $(20 + R_L)$, we get $10(20 + R_L) = 50 R_L$.$200 + 10 R_L = 50 R_L$.$200 = 40 R_L$.$R_L = \frac{200}{40} = 5 \text{ k}\Omega$.

Class 12 Physics Semiconductor Electronics Valve Electronics

Medium

$A$ triode has a transconductance $(g_m)$ of $2.5 \text{ mA/V}$ and an anode resistance $(r_p)$ of $20 \text{ k}\Omega$. If it is used as an amplifier with an amplification factor of $10$, what is the load resistance $(R_L)$ connected to the plate circuit in $\text{k}\Omega$?

A
$5$
B
$20$
C
$10$
D
$1$

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Class 12

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Semiconductor Electronics

Subtopic

Valve Electronics

In a triode,${g_m} = 2 \times 10^{-3} \, \Omega^{-1}$,$\mu = 42$,and the resistance load $R_L = 50 \, \text{k}\Omega$. The voltage amplification obtained from this triode will be:

Medium

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The amplification produced by a triode is due to the action of

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In the space charge limited region,the plate current in a diode is $10\, mA$ for a plate voltage of $150\, V$. If the plate voltage is increased to $600\, V$,then the plate current will be.......$mA$.

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The figure represents the variation of triode parameters ($\mu$, $r_p$, or $g_m$) with the plate current. The correct variations of $\mu$ and $r_p$ are given, respectively, by the curves:

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In the circuit of a triode valve,there is no change in the plate current when the plate potential is increased from $200 \ V$ to $220 \ V$ and the grid potential is decreased from $-0.5 \ V$ to $-1.3 \ V$. The amplification factor of this valve is

Medium

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$A$ triode has a transconductance $(g_m)$ of $2.5 \text{ mA/V}$ and an anode resistance $(r_p)$ of $20 \text{ k}\Omega$. If it is used as an amplifier with an amplification factor of $10$, what is the load resistance $(R_L)$ connected to the plate circuit in $\text{k}\Omega$?

Similar Questions

In a triode,${g_m} = 2 \times 10^{-3} \, \Omega^{-1}$,$\mu = 42$,and the resistance load $R_L = 50 \, \text{k}\Omega$. The voltage amplification obtained from this triode will be:

The amplification produced by a triode is due to the action of

In the space charge limited region,the plate current in a diode is $10\, mA$ for a plate voltage of $150\, V$. If the plate voltage is increased to $600\, V$,then the plate current will be.......$mA$.

The figure represents the variation of triode parameters ($\mu$, $r_p$, or $g_m$) with the plate current. The correct variations of $\mu$ and $r_p$ are given, respectively, by the curves:

In the circuit of a triode valve,there is no change in the plate current when the plate potential is increased from $200 \ V$ to $220 \ V$ and the grid potential is decreased from $-0.5 \ V$ to $-1.3 \ V$. The amplification factor of this valve is

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