Which of the following relations are correct according to Boolean algebra?

To get the truth table shown, from the following logic circuit, the Gate $G$ should be

$A$	$B$	$Y$
$0$	$0$	$0$
$0$	$1$	$0$
$1$	$0$	$1$
$1$	$1$	$1$

To get an output $Y = 1$ in the given circuit,which of the following inputs will be correct?

$A$ gate in which all the inputs must be low to get a high output is called:

The Boolean expression $Y = A \bar{B} C + \bar{A} \bar{C}$ can be realized with which of the following gate configurations?
$A.$ One $3$-input $\text{AND}$ gate,$2$ $\text{NOT}$ gates,one $2$-input $\text{AND}$ gate,and one $2$-input $\text{OR}$ gate.
$B.$ One $3$-input $\text{AND}$ gate,$2$ $\text{NOT}$ gates,one $2$-input $\text{NAND}$ gate,and one $2$-input $\text{OR}$ gate.
$C.$ One $3$-input $\text{OR}$ gate,$3$ $\text{NOT}$ gates,and one $2$-input $\text{AND}$ gate.
Choose the correct answer from the options given below.

Identify the correct output signal $Y$ in the given combination of gates (as shown) for the given inputs $A$ and $B$.