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(C) Germanium $(Ge)$ is a group-$14$ element,and Antimony $(Sb)$ is a group-$15$ element.When $Sb$ is added to $Ge$,it acts as a pentavalent dopant.Fo

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The number of free electrons becomes greater than the number of holes in the semiconductor.

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(C) Germanium $(Ge)$ is a group-$14$ element,and Antimony $(Sb)$ is a group-$15$ element.When $Sb$ is added to $Ge$,it acts as a pentavalent dopant.Four electrons of $Sb$ form covalent bonds with $Ge$ atoms,and the fifth electron becomes a free charge carrier.Since the number of free electrons increases significantly,it becomes an $N$-type semiconductor.In an $N$-type semiconductor,the concentration of free electrons is much greater than the concentration of holes $(n_e \gg n_h)$.

When a small amount of antimony impurity is added to a germanium crystal,what happens?

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