The output of an OR gate is connected to both | vedclass

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(C) Let the inputs of the $OR$ gate be $A$ and $B$. The output of the $OR$ gate is $Y_1 = A + B$.This output $Y_1$ is connected to both inputs of a $N

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$NOR$ gate

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(C) Let the inputs of the $OR$ gate be $A$ and $B$. The output of the $OR$ gate is $Y_1 = A + B$.This output $Y_1$ is connected to both inputs of a $NAND$ gate. Let the inputs of the $NAND$ gate be $X_1$ and $X_2$,where $X_1 = X_2 = Y_1 = A + B$.The output of the $NAND$ gate is $Y = \overline{X_1 \cdot X_2} = \overline{(A + B) \cdot (A + B)} = \overline{A + B}$.The expression $\overline{A + B}$ represents the Boolean operation of a $NOR$ gate.Therefore,the combination is equivalent to a $NOR$ gate.

$A$	$B$	$Y$
$0$	$0$	$1$
$0$	$1$	$0$
$1$	$0$	$1$
$1$	$1$	$0$

The output of an $OR$ gate is connected to both inputs of a $NAND$ gate. This combination is equivalent to a:

Similar Questions

Consider the following statements regarding digital signals:
$(i)$ provide a continuous set of values
(ii) represent values as discrete steps
(iii) can utilise binary system
(iv) are in the form of rectangular waves
Then the true statements are:

How many $NAND$ gates are used to form an $AND$ gate?

The symbolic representations of four logic gates are given below. The logic symbols for $OR$,$NOT$,and $NAND$ gates are respectively:

The truth table for the circuit shown in the figure is

$A$ logic circuit provides the output $Y$ as per the following truth table:

$A$ $B$ $Y$

$0$ $0$ $1$

$0$ $1$ $0$

$1$ $0$ $1$

$1$ $1$ $0$

The expression for the output $Y$ is:

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