(B) In Boolean algebra,the $OR$ operation between a variable and its complement always results in $1$.Case $1$: If $A = 1$,then $\bar{A} = 0$. Therefo

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(B) In Boolean algebra,the $OR$ operation between a variable and its complement always results in $1$.Case $1$: If $A = 1$,then $\bar{A} = 0$. Therefore,$A + \bar{A} = 1 + 0 = 1$.Case $2$: If $A = 0$,then $\bar{A} = 1$. Therefore,$A + \bar{A} = 0 + 1 = 1$.Thus,for any value of $A$,$A + \bar{A} = 1$.