The Boolean equation $A \cdot \bar{A} =$ ......
- A$0$
- B$1$
- C$A$
- D$\bar{A}$
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Similar Questions
Draw the output signals $C_1$ and $C_2$ for the given combination of gates as shown in the figure.
Medium
View SolutionThe two combinations of $NAND$ gates shown in the figures are equivalent to:
The given truth table is for:
$A$ $B$ $Y$ $0$ $0$ $1$ $0$ $1$ $1$ $1$ $0$ $1$ $1$ $1$ $0$
| $A$ | $B$ | $Y$ |
|---|---|---|
| $0$ | $0$ | $1$ |
| $0$ | $1$ | $1$ |
| $1$ | $0$ | $1$ |
| $1$ | $1$ | $0$ |
$A$ $NOR$ gate and a $NAND$ gate are connected as shown in the figure. Two different sets of inputs are given to this setup. In the first case,the inputs to the gates are $A=0, B=0, C=0$. In the second case,the inputs are $A=1, B=0, C=1$. The output $D$ in the first case and second case respectively are
In the Boolean algebra,$(\overline {\bar A \cdot \bar B} ) \cdot A$ is equal to:
Medium
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