For an electric dipole with charge q = 2 time | vedclass

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(B) The dipole moment $p$ is given by the product of the charge $q$ and the separation distance $d$:$p = q 	imes d = (2 	imes 10^{-6} \ C) 	imes (0

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$10 	imes 10^{-3} \ Nm$

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(B) The dipole moment $p$ is given by the product of the charge $q$ and the separation distance $d$:$p = q 	imes d = (2 	imes 10^{-6} \ C) 	imes (0.01 \ m) = 2 	imes 10^{-8} \ Cm$.The torque $	au$ acting on a dipole in an electric field is given by $	au = pE \sin(	heta)$.For maximum torque,$\sin(	heta) = 1$ (when the dipole is perpendicular to the electric field).Therefore,$	au_{max} = p 	imes E$.Substituting the values:$	au_{max} = (2 	imes 10^{-8} \ Cm) 	imes (5 	imes 10^{5} \ N/C) = 10 	imes 10^{-3} \ Nm$.

For an electric dipole with charge $q = 2 \times 10^{-6} \ C$ and separation distance $d = 0.01 \ m$,if the external electric field is $E = 5 \times 10^{5} \ N/C$,calculate the maximum torque acting on the dipole.

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