Two capacitors of $1 \ \mu F$ and $2 \ \mu F$ are connected in series. This combination is charged to a potential difference of $120 \ V$. What is the potential difference across the $1 \ \mu F$ capacitor in volts?

In the following circuit,the equivalent capacitance between terminal $A$ and terminal $B$ is: (in $\mu F$)

Four identical capacitors are connected in series with a battery of $emf$ $10 \ V$. Point $X$ is grounded. Find the potential at point $A$ in $V$.

Four metallic plates,each of surface area (of one side) $A$,are placed at a distance $d$ apart from each other. The two outer plates are connected to a point $P$ and the two inner plates are connected to another point $Q$ as shown in the figure below. Then,the capacitance of the system is

Four identical rectangular plates with length,$l = 2 \, cm$ and breadth,$b = \frac{3}{2} \, cm$ are arranged as shown in the figure. The equivalent capacitance between $A$ and $C$ is $\frac{x \varepsilon_{0}}{d}$. The value of $x$ is (Round off to the Nearest Integer).

Capacitors of $C, 2C, 4C, \dots, \infty$ are connected in parallel. What will be their equivalent capacitance?