Two small spheres of masses M_1 and M_2 are s | vedclass

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Question

(B) For each sphere,three forces are acting: $(1)$ Tension force $(T)$,$(2)$ Gravitational force $(Mg)$,and $(3)$ Electrostatic repulsive force $(F)$.

Vedclass · Accepted Answer

$M_1 = M_2$

Vedclass · Answer

(B) For each sphere,three forces are acting: $(1)$ Tension force $(T)$,$(2)$ Gravitational force $(Mg)$,and $(3)$ Electrostatic repulsive force $(F)$.For the first sphere at equilibrium:$T_1 \cos 	heta_1 = M_1 g$ and $T_1 \sin 	heta_1 = F$Dividing these,we get: $	an 	heta_1 = \frac{F}{M_1 g}$For the second sphere at equilibrium:$T_2 \cos 	heta_2 = M_2 g$ and $T_2 \sin 	heta_2 = F$Dividing these,we get: $	an 	heta_2 = \frac{F}{M_2 g}$Since the electrostatic force $F$ between the two spheres is the same (by Newton's third law),for $	heta_1 = 	heta_2$,we must have $	an 	heta_1 = 	an 	heta_2$.Therefore,$\frac{F}{M_1 g} = \frac{F}{M_2 g}$,which implies $M_1 = M_2$.

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