Three identical charges of 10 mu C are place | vedclass

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(C) The electrostatic potential energy $U$ of a system of three point charges is given by the formula:$U = \frac{1}{4\pi\epsilon_0} \left( \frac{q_1q_

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$27$

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(C) The electrostatic potential energy $U$ of a system of three point charges is given by the formula:$U = \frac{1}{4\pi\epsilon_0} \left( \frac{q_1q_2}{r_{12}} + \frac{q_2q_3}{r_{23}} + \frac{q_3q_1}{r_{31}} ight)$Given: $q_1 = q_2 = q_3 = 10 \ \mu C = 10 	imes 10^{-6} \ C = 10^{-5} \ C$,and side $a = 10 \ cm = 0.1 \ m = 10^{-1} \ m$.Since the triangle is equilateral,$r_{12} = r_{23} = r_{31} = a = 10^{-1} \ m$.Substituting the values:$U = 3 	imes \left( \frac{k \cdot q^2}{a} ight)$$U = 3 	imes \left( \frac{9 	imes 10^9 	imes (10^{-5})^2}{10^{-1}} ight)$$U = 3 	imes \left( \frac{9 	imes 10^9 	imes 10^{-10}}{10^{-1}} ight)$$U = 3 	imes 9 	imes 10^9 	imes 10^{-10} 	imes 10^1$$U = 27 	imes 10^0 = 27 \ J$.

Three identical charges of $10 \ \mu C$ are placed at the vertices of an equilateral triangle of side $10 \ cm$. The electrostatic potential energy of the system is ....... $J$.

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