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(B) Consider two charges $+q$ and $-q$ separated by a distance $2a$. Let $P$ be a point on the perpendicular bisector at a distance $x$ from the midpo

Vedclass · Accepted Answer

The electric potential is zero.

Vedclass · Answer

(B) Consider two charges $+q$ and $-q$ separated by a distance $2a$. Let $P$ be a point on the perpendicular bisector at a distance $x$ from the midpoint.The electric potential $V$ at point $P$ due to a charge $q$ at distance $r$ is given by $V = \frac{1}{4 \pi \varepsilon_0} \frac{q}{r}$.The distance of point $P$ from both charges $+q$ and $-q$ is $r = \sqrt{x^2 + a^2}$.The potential due to $+q$ is $V_1 = \frac{1}{4 \pi \varepsilon_0} \frac{q}{\sqrt{x^2 + a^2}}$.The potential due to $-q$ is $V_2 = -\frac{1}{4 \pi \varepsilon_0} \frac{q}{\sqrt{x^2 + a^2}}$.The total electric potential at point $P$ is $V = V_1 + V_2 = \frac{1}{4 \pi \varepsilon_0} \frac{q}{\sqrt{x^2 + a^2}} - \frac{1}{4 \pi \varepsilon_0} \frac{q}{\sqrt{x^2 + a^2}} = 0$.Thus,the electric potential at any point on the perpendicular bisector of an electric dipole is zero.

At any point on the perpendicular bisector of the line joining two equal and opposite charges,which of the following is true?

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