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(B) The intensity of radiation at Earth is $I = 1.4 	imes 10^3 \ W/m^2$.Total power emitted by the Sun is $P = I 	imes A = I 	imes (4\pi r^2)$.$P =

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$3.8 	imes 10^{14} \ kg$

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(B) The intensity of radiation at Earth is $I = 1.4 	imes 10^3 \ W/m^2$.Total power emitted by the Sun is $P = I 	imes A = I 	imes (4\pi r^2)$.$P = 1.4 	imes 10^3 	imes 4 	imes 3.14 	imes (1.5 	imes 10^{11})^2$.$P = 1.4 	imes 10^3 	imes 4 	imes 3.14 	imes 2.25 	imes 10^{22} \approx 3.956 	imes 10^{26} \ J/s$.Using Einstein's mass-energy equivalence $E = \Delta m c^2$, the rate of mass loss is $\frac{\Delta m}{t} = \frac{P}{c^2}$.$\frac{\Delta m}{t} = \frac{3.956 	imes 10^{26}}{(3 	imes 10^8)^2} = \frac{3.956 	imes 10^{26}}{9 	imes 10^{16}} \approx 4.395 	imes 10^9 \ kg/s$.Mass lost per day = $\frac{\Delta m}{t} 	imes 86400 \ s$.Mass lost per day = $4.395 	imes 10^9 	imes 86400 \approx 3.8 	imes 10^{14} \ kg$.

The Sun emits radiation in all directions. The Earth receives approximately $1.4 \ kW/m^2$ of radiation per second. The distance between the Sun and the Earth is $1.5 \times 10^{11} \ m$. How much mass does the Sun lose per day? $(1 \ \text{day} = 86400 \ s)$

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