The mass of a proton is 1.0073 , u and that o | vedclass

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(C) The binding energy $(B.E.)$ is calculated using the mass defect formula: $B.E. = [Z m_p + (A - Z) m_n - M_{nucleus}] c^2$.Here,$Z = 2$ (number of

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$28.4 \, MeV$

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(C) The binding energy $(B.E.)$ is calculated using the mass defect formula: $B.E. = [Z m_p + (A - Z) m_n - M_{nucleus}] c^2$.Here,$Z = 2$ (number of protons),$A = 4$ (mass number),$m_p = 1.0073 \, u$,$m_n = 1.0087 \, u$,and $M_{nucleus} = 4.0015 \, u$.Mass defect $\Delta m = [2(1.0073) + 2(1.0087) - 4.0015] \, u$.$\Delta m = [2.0146 + 2.0174 - 4.0015] \, u = [4.0320 - 4.0015] \, u = 0.0305 \, u$.Since $1 \, u = 931.5 \, MeV/c^2$,the binding energy is $B.E. = 0.0305 	imes 931.5 \, MeV \approx 28.4 \, MeV$.

The mass of a proton is $1.0073 \, u$ and that of a neutron is $1.0087 \, u$. The binding energy of $_2He^4$ is .... ($u = \text{atomic mass unit}$,mass of helium nucleus = $4.0015 \, u$)

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