In the Bohr model of the hydrogen atom,the an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The angular velocity $\omega$ is given by the relation $\omega = \frac{v}{r}$.According to Bohr's theory for a hydrogen atom:$1$. The orbital velo

Vedclass · Accepted Answer

$\omega_n \propto 1/n^3$

Vedclass · Answer

(C) The angular velocity $\omega$ is given by the relation $\omega = \frac{v}{r}$.According to Bohr's theory for a hydrogen atom:$1$. The orbital velocity of an electron in the $n^{th}$ orbit is $v_n \propto \frac{1}{n}$.$2$. The radius of the $n^{th}$ orbit is $r_n \propto n^2$.Substituting these proportionalities into the angular velocity formula:$\omega_n = \frac{v_n}{r_n} \propto \frac{1/n}{n^2} = \frac{1}{n^3}$.Therefore,$\omega_n \propto \frac{1}{n^3}$.

In the Bohr model of the hydrogen atom,the angular velocity $\omega_n$ of the electron depends on the principal quantum number $n$ as:

Similar Questions

An ionic atom equivalent to a hydrogen atom has a wavelength equal to $1/4$ of the wavelength of the corresponding hydrogen line. The ion is:

The ratio of the velocity of an electron in the ground state of a hydrogen atom to the velocity of light (in $CGS$ units) is:

Find the radius of $Be^{3+}$ ions in its ground state assuming Bohr's model to be valid $(a_0 = 53 \ pm)$. (in $pm$)

When an electron falls from a higher energy level to a lower energy level,the difference in energy is emitted as electromagnetic radiation. Why can it not be emitted as other forms of energy?

In the Bohr model of the hydrogen atom,the linear momentum of the electron depends on the principal quantum number $n$ as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module