Nuclear fission is possible because the binding energy per nucleon ...

Nucleus $A$ having $Z=17$ and an equal number of protons and neutrons has $1.2 \, MeV$ binding energy per nucleon. Another nucleus $B$ of $Z=12$ has a total of $26$ nucleons and $1.8 \, MeV$ binding energy per nucleon. The difference in binding energy of $B$ and $A$ will be $........... \, MeV$.

$A$ heavy nucleus having mass number $200$ gets disintegrated into two small fragments of mass numbers $80$ and $120$. If binding energy per nucleon for the parent atom is $6.5 \text{ MeV}$ and for the daughter nuclei is $7 \text{ MeV}$ and $8 \text{ MeV}$ respectively, then the energy released in the decay will be: (in $\text{ MeV}$)

The average binding energy per nucleon in the nucleus of an atom is approximately ........

The electrostatic energy of $Z$ protons uniformly distributed throughout a spherical nucleus of radius $R$ is given by $E = \frac{3}{5} \frac{Z(Z-1) e^2}{4 \pi \varepsilon_0 R}$. The measured masses of the neutron,${ }_1^1 H$,${ }_7^{15} N$,and ${ }_8^{15} O$ are $1.008665 \ u$,$1.007825 \ u$,$15.000109 \ u$,and $15.003065 \ u$,respectively. Given that the radii of both the ${ }_7^{15} N$ and ${ }_8^{15} O$ nuclei are the same,$1 \ u = 931.5 \ MeV/c^2$ ($c$ is the speed of light),and $e^2 / (4 \pi \varepsilon_0) = 1.44 \ MeV \ fm$. Assuming that the difference between the binding energies of ${ }_7^{15} N$ and ${ }_8^{15} O$ is purely due to the electrostatic energy,the radius of either of the nuclei is $(1 \ fm = 10^{-15} \ m)$: (in $fm$)

Binding energy of a certain nucleus is $18 \times 10^8 \ J$. How much is the difference between the total mass of all the nucleons and the nuclear mass of the given nucleus (in $\mu g$)?