If a container is filled with a mixture of $H_2$ and $O_2$ gases at the same temperature,then:

  • A
    $H_2$ has a higher $rms$ velocity.
  • B
    $O_2$ has a higher $rms$ velocity.
  • C
    $O_2$ has a higher average kinetic energy.
  • D
    $H_2$ has a higher average kinetic energy.

Explore More

Similar Questions

For a mixture of three different gases with molecular masses $m_1 > m_2 > m_3$ at the same temperature,what is the relationship between their root mean square speeds $(v_{rms})$ and average kinetic energies $(\bar{K})$?

At which temperature is the r.m.s. velocity of a hydrogen molecule equal to that of an oxygen molecule at $47^{\circ} C$ (in $\,K$)?

The root mean square speed of smoke particles of mass $5 \times 10^{-17} \, kg$ in their Brownian motion in air at $NTP$ is approximately $....... \, mm \, s^{-1}$. [Given $k = 1.38 \times 10^{-23} \, J \, K^{-1}$ and $T = 293 \, K$]

The rms speed of an oxygen molecule in a vessel at a particular temperature is $\left(1+\frac{5}{x}\right)^{\frac{1}{2}} v$,where $v$ is the average speed of the molecule. The value of $x$ will be: (Take $\pi=\frac{22}{7}$)

If the root mean square velocity of the molecules of hydrogen at $NTP$ is $1.84 \, km/s$,calculate the root mean square velocity of oxygen molecule at $NTP$. The molecular weights of hydrogen and oxygen are $2$ and $32$ respectively.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo